Simplify: x(x ^ 2 + x + 1) - 6 and find its value for: i) ii) iv) x = 0 x = 1 x = - 1 x = 2
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Topic : Algebra
Given : x(x² + x + 1) - 6
Solve for :
- Simplification.
- Value at x = 0, 1, -1 and 2.
Solution :
For simplification of given expression, we need to multiply,
Simplifying
x(x² + x + 1) - 6
x(x²) + x(x) + x(1) - 6
x³ + x² + x - 6 . . . . . . ( Simplified Value )
Calculating values for given values,
We will put given value in place of 'x' to get value of whole expression.
i) x = 0
Put x = 0, in obtained expression,
x³ + x² + x - 6
(0)³ + (0)² + (0) - 6
0 + 0 + 0 - 6
-6
ii) x = 1
Put x = 1, in obtained expression,
x³ + x² + x - 6
(1)³ + (1)² + 1 - 6
1 + 1 + 1 - 6
3 - 6
-3
iii) x = -1
Put x = -1, in obtained expression,
x³ + x² + x - 6
(-1)³ + (-1)² + (-1) - 6
-1 + 1 - 1 - 6
1 - 8
-7
iv ) x = 2
Put x = 2, in obtained expression,
x³ + x² + x - 6
(2)³ + (2)² + 2 - 6
8 + 4 + 2 - 6
14 - 6
8
Answer :
- Simplified value : x³ + x² + x - 6
- Respective value for given values are -6, -3, -7 and 8.
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