Question

Simplify : (x - y)3 – (x3 - y3).​

Answer 1

Answer:

answer is 0

Step-by-step explanation:

3x-3y-(x3-y3)

3x-3y-3x+3y

therefore

3x-3x-3y+3y

=0

Answer 2

Answer:

Step-by-step explanation:

$(x-y)^{3}$ = $(a-b)^{3}$

$(a-b)^{3}$ = $a^{3} -3a^{2}b+3ab^{2}-b^{3}$  

= $x^{3} -3x^{2}y+3xy^{2}-y^{3}$

$x^{3}-y^{3}$= $a^{3} -b^{3}$

$a^{3} - b^{3}$ = (a-b) $(a^{2} +ab +b^{2})$

$x^{3}-y^{3}$ = $(x-y)$  $(x^{2} +xy+y^{2})$

=  $x^{3} -3x^{2}y+3xy^{2}-y^{3}$ - $(x-y)$ $(x^{2} +xy+y^{2})$

= $(x-y)$ $(x^{2} +xy+y^{2})$ = $x^{3} -y^{3}$

= $x^{3}$ - $x^{3}$  + $y^{3}$ - $y^{3}$  $-3x^{2}y+3xy^{2}$

=$-3x^{2}y+3xy^{2}$

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