Question

simplify x-y whole square ÷ x square-y square

Answer 1

(x - y)²/(x² - y²)
Do you know , algebraic identities ,
e.g., (a² - b²) = (a - b)(a + b) , use this here in place of (x² - y²)

Now, (x - y)²/(x - y)(x + y)
= (x - y)(x - y)/(x - y)(x + y)
= (x - y)(x + y)

Hence, answer should be (x -y)/(x + y)

Answer 2

We can write $(x-y)^{2}$ as (x-y)*(x-y)
We also have the identity $a^{2} - b^{2}$ = (a+b)*(a-b)
Using these two identities, we can go ahead and solve this problem.

Hence, the problem takes the form $\frac{(x-y)(x-y)}{(x+y)(x-y)}$
Canceling out the (x-y) present in both the numerator and the denominator, it takes the form $\frac{x-y}{x+y}$, which is the required answer.

Thus, the simplified form of $\frac{(x-y)^2}{x^2-y^2}$ is  $\frac{x-y}{x+y}$