Question

simplify : x²n+³ .x(²n+¹)(n+²) /(x³)²n+1 .xn(²n+¹)​

Answer 1

Answer:

Take (n−1)!, (n+1)!, (n+3)! common from R1, R2, R3 respectively

∴(n−1)!(n+1)!(n+3)!D

=∣∣∣∣∣∣∣∣111(n+1)n(n+3)(n+2)(n+5)(n+4)(n+3)(n+2)(n+5)(n+4)(n+7)(n+6)∣∣∣∣∣∣∣∣

Making two zeros in column I by applying R3−R2 ad R2−R1, we have

E=∣∣∣∣∣∣∣∣100(n+1)n4n+64n+14(n+3)(