simplify : x²n+³ .x(²n+¹)(n+²) /(x³)²n+1 .xn(²n+¹)
Answers
Answered by
2
Answer:
Take (n−1)!, (n+1)!, (n+3)! common from R1, R2, R3 respectively
∴(n−1)!(n+1)!(n+3)!D
=∣∣∣∣∣∣∣∣111(n+1)n(n+3)(n+2)(n+5)(n+4)(n+3)(n+2)(n+5)(n+4)(n+7)(n+6)∣∣∣∣∣∣∣∣
Making two zeros in column I by applying R3−R2 ad R2−R1, we have
E=∣∣∣∣∣∣∣∣100(n+1)n4n+64n+14(n+3)(
Similar questions