Math, asked by chittarimurali94411, 4 months ago

simplify:
ysin^6x+cos^6x+3sin^6x.cos^2x


Pls answer it correctly

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Answers

Answered by subhasmitasahoo82
2

Step-by-step explanation:

y=

sin

6

x+cos

6

x

1

Weknowthata

3

+b

3

=(a+b)

3

−3ab(a+b)

AndSomeImpResultsaresin

2

x+cos

2

x=1and2sinxcosx=sin2x

Ifa=sin

2

xandb=cos

2

xThen

sin

6

x+cos

6

x=(sin

2

x+cos

2

x)

3

−3sin

2

xcos

2

x(sin

2

x+cos

2

x)

Sowehavesin

6

x+cos

6

x=1−3sin

2

xcos

2

x

sin

6

x+cos

6

x=1−

4

3

sin

2

2x

Forytobemaximumsin

6

x+cos

6

xshouldbeminimum

Sosin

2

2x=1

y

max

=

1−

4

3

1

=4

Answered by kargetikavita8
0

Answer:

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