Simplifyand then find the value & form=2 n=1 (m+n) (m²=n²)+(m-n) (m²+n²)
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Answer:
Consider
(m+n)
2
m
2
−n
2
×
m
3
−n
3
m
2
+mn+n
2
We know that, (a
2
−b
2
)=(a+b)(a−b) and a
3
−b
3
=(a−b)(a
2
+ab+b
2
)
(m+n)
2
m
2
−n
2
×
m
3
−n
3
m
2
+mn+n
2
=
(m+n)
2
(m+n)(m−n)
×
(m−n)(m
2
+mn+n
2
)
m
2
+mn+n
2
=
m+n
m−n
×
m−n
1
=
m+n
1
∴
(m+n)
2
m
2
−n
2
×
m
3
−n
3
m
2
+mn+n
2
=
m+n
1
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