Question

Simplity: (2a)(3+b+ab²)​

Answer 1

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Answer 2

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$Simplity: (2a)(3+b+ab²)

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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$= > (2a)(3+b+ab²)$

$\bold{= > 6a + 2ab + 2 {a}^{2} {b}^{2} }✓$

=>>further solving --

=>Here,we notice that 6,2&2 are multiples of 2 .so,take 2as a common from all terms.

$= > 2(3a + ab + {a}^{2} {b}^{2} )$

=>In the all term 'a' is common so, taking 'a' common .

$= > 2(a(3 + b) + a{b}^{2} )$

$= > 2a(3 + b + a {b}^{2} )$

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