Math, asked by singhsujata9999, 2 months ago

. Simplity
(i) 3/45 - V125+ 200 - 50​

Answers

Answered by joshisangeeta410
0

Answer:

1

Divide the numbers

3

4

5

1

1

2

5

+

2

0

0

5

0

{\color{#c92786}{\frac{3}{45}}}-1v^{125}+200-50

453−1v125+200−50

1

1

5

1

1

2

5

+

2

0

0

5

0

{\color{#c92786}{\frac{1}{15}}}-1v^{125}+200-50

151−1v125+200−50

2

Add the numbers

1

1

5

1

2

5

+

2

0

0

5

0

{\color{#c92786}{\frac{1}{15}}}-v^{125}+{\color{#c92786}{200}}{\color{#c92786}{-50}}

151−v125+200−50

2

2

5

1

1

5

1

2

5

{\color{#c92786}{\frac{2251}{15}}}-v^{125}

152251−v125

3

Rearrange terms

2

2

5

1

1

5

1

2

5

{\color{#c92786}{\frac{2251}{15}-v^{125}}}

152251−v125

1

2

5

+

2

2

5

1

1

5

{\color{#c92786}{-v^{125}+\frac{2251}{15}}}

−v125+152251

Solution

1

2

5

+

2

2

5

1

Step-by-step explanation:

3

4

5

1

1

2

5

+

2

0

0

5

0

{\color{#c92786}{\frac{3}{45}}}-1v^{125}+200-50

453−1v125+200−50

1

1

5

1

1

2

5

+

2

0

0

5

0

{\color{#c92786}{\frac{1}{15}}}-1v^{125}+200-50

151−1v125+200−50

2

Add the numbers

1

1

5

1

2

5

+

2

0

0

5

0

{\color{#c92786}{\frac{1}{15}}}-v^{125}+{\color{#c92786}{200}}{\color{#c92786}{-50}}

151−v125+200−50

2

2

5

1

1

5

1

2

5

{\color{#c92786}{\frac{2251}{15}}}-v^{125}

152251−v125

3

Rearrange terms

2

2

5

1

1

5

1

2

5

{\color{#c92786}{\frac{2251}{15}-v^{125}}}

152251−v125

1

2

5

+

2

2

5

1

1

5

{\color{#c92786}{-v^{125}+\frac{2251}{15}}}

−v125+152251

Solution

Answered by rishabhdubey626
0

Answer:

utarjdoyoysaeyfup8bf6

yf6fpmiyiiyeyurrny

327900%stsyd"gfsrhii/gdago

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