Question

simpliyfy root2 (root6 - root 8 ) + root 3 (root 27 - root 6)

Answer 1

Hi...☺

Here is your answer...✌

√2 (√6 - √8) + √3(√27 - √6)

= √2(√2×√3 - 2√2) + √3(3√3 - √2×√3)

= 2√3 - 2×2 + 3×3 - 3√2

= 2√3 - 4 + 9 - 3√2

= 5 + 2√3 - 3√2

Answer 2

Answer:

The correct answer to this question is $5 + 2 \sqrt{3} - 3\sqrt{2}$

Step-by-step explanation:

Given- $\sqrt{2} ( \sqrt{6} - \sqrt{8} ) + \sqrt{3} ( \sqrt{27} - \sqrt{6} )$

To Find - simplify the equation -

According to the question -

$\sqrt{2} ( \sqrt{6} - \sqrt{8} ) + \sqrt{3} ( \sqrt{27} - \sqrt{6} )$

$\sqrt{2}( \sqrt{2}$ × $\sqrt{3} - 2 \sqrt{2} ) + \sqrt{3} ( 3 \sqrt{3} - \sqrt{2}$ × $\sqrt{3} )$

$2\sqrt{3} - 2$ × $2 + 3$ × $3 - 3\sqrt{2}$

$2\sqrt{3} - 4$ $+ 9 - 3\sqrt{2}$

$5 + 2 \sqrt{3} - 3\sqrt{2}$

#SPJ2