Question

simply 1/√3+2 +1/√3-2​

Answer 1

Answer:

by ratinlizatio 1/√3

(√3+6+√3-6) /3

2√3/3

Answer 2

Answer:

$- 2 \sqrt{3}$

Step-by-step explanation:

$\frac{1}{ \sqrt{3} + 2 } + \frac{1}{ \sqrt{3} - 2}$

rationalising both the terms... $(\frac{1}{ \sqrt{3} + 2} \times \frac{ \sqrt{3} - 2 }{ \sqrt{3 } - 2 }) + (\frac{1}{ \sqrt{3} - 2 } \times \frac{ \sqrt{3} + 2 }{ \sqrt{3} + 2 } )$

$( \frac{ \sqrt{3} - 2}{3 - 4} ) + ( \frac{ \sqrt{3} + 2}{3 - 4} )$

$(\frac{ \sqrt{3} - 2 }{ - 1} ) + ( \frac{ \sqrt{3} + 2}{ - 1} )$

$2 - \sqrt{3} + ( - \sqrt{3} - 2)$

$2 - \sqrt{3 } - \sqrt{3} - 2$

$- 2 \sqrt{3}$

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