Question

Simply (1+tan^2¤) (1-sin¤) (1+cos ¤) Please help I need the answer asap !!!!​

Answer 1

Answer:

LHS,

( 1 + tan²∅)( 1 - sin∅)(1 + sin∅)

= ( sec²∅)( 1 - sin∅)( 1 - sin∅)

= sec²∅( 1 - sin²∅)

= sec²∅ × cos²∅

= 1.

Explanation:

formula used

$1 + { \tan( \alpha ) }^{2} = { \sec( \alpha ) }^{2} \\ 1 - { \cos( \alpha ) }^{2} = { \sin( \alpha ) }^{2} \\ \frac{1}{ \sec( \alpha ) } = \cos( \alpha )$