Question

simply
(2+√3/2-√3) + (2-√3/2+√3) + (√3-1/√3+1)​

Answer 1

Solution : (ʘᴗʘ)

$\red{ \frac{2 + \sqrt{3} }{2 - \sqrt{3} } + \frac{2 - \sqrt{3} }{2 + \sqrt{3} } + \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } }$

$\orange{( \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} }) + (\frac{2 - \sqrt{3} }{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } ) + ( \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } + \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } )}$

$\green{ \frac{ {(2)}^{2} + 2(2)( \sqrt{3} ) + {(3)}^{2} }{ {(2)}^{2} - { (\sqrt{3} )}^{2} } + \frac{{(2)}^{2} - 2(2)( \sqrt{3} ) + ( \sqrt{3}) ^{2} }{ {(2)}^{2} - {( \sqrt{3})}^{2} } + \frac{{ (\sqrt{3} )}^{2} - 2( \sqrt{3} )(1) + {(1)}^{2} }{ {( \sqrt{3}) }^{2} - {(1)}^{2} }}$

$\blue{ (4 + 4 \sqrt{3} + 3) + (4 - 4 \sqrt{3} + 3) + \frac{3 - 2 \sqrt{3} + 1 }{2} }$

$\purple{4 + 4 \sqrt{3} + 4 - 4 \sqrt{3} + 2 - \sqrt{3} }$

$\boxed{ \pink { \large{16 - \sqrt{3} }}}$

Hope It May Help You.... (≧▽≦)

Happy Learning... (◠‿・)