Simply (2a²b)²(–a²b)³ in indices
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Answer:
-4a¹⁰b⁵
Step-by-step explanation:
(2a²b)²(-a²b)³
2a²b×2a²b×(-a²b×-a²b×-a²b)
2×2×a²×a²×b×b{-(a²×a²×a²×b×b×b)}
same base (in multiplication)then addition of its power
4a⁴b²(-a⁶×b³)
-4a⁴×a⁶×b²×b³
-4a¹⁰b⁵
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