Math, asked by harkishan9720, 10 hours ago

Simply (2a²b)²(–a²b)³ in indices

Answers

Answered by akp747205
2

Answer:

-4a¹⁰b⁵

Step-by-step explanation:

(2a²b)²(-a²b)³

2a²b×2a²b×(-a²b×-a²b×-a²b)

2×2×a²×a²×b×b{-(a²×a²×a²×b×b×b)}

same base (in multiplication)then addition of its power

4a⁴b²(-a⁶×b³)

-4a⁴×a⁶×b²×b³

-4a¹⁰b⁵

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