Math, asked by mundrupadma4, 24 days ago

simply 2log5-3log2+4log3​

Answers

Answered by PASSENGERS15432
0

Answer:

solution:-

using formulas

log m×n= log m + log n

=>log 6 + 2log5+log 4 -log 3 -log 2 =

log 2×3 + 2log 5 + log 2×2 - log 3 -log 2

=> log 2 + log 3 +2 log 5 +log 2+ log 2 - log 3 - log 2

=> 2log 2 +2 log 5 = 2( log 2 + log 5)

=> 2log 2×5 = 2log 10 = 2 answer

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