simply 3+6×(5+4)÷3_7
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Heya,
3 + 6 × (5+4) ÷ 3 - 7
This should simplified using BODMAS rule.
B - Bracket
O - of
D - Division
M - Multiplication
A - Addition
S - Subtraction
=> First we should remove the bracket 3 + 6 × (5+4) ÷ 3 - 7
3 + 6 × 9 ÷ 3 - 7
=> Second division rule
3 + 6 × 3 - 7
=> Third Multiplication rule
3 + 18 - 7
=> Fourth Addison rule
21 - 7
=> And lastly subtraction rule
14
Hope my answer helps you :)
Regards,
Shobana
3 + 6 × (5+4) ÷ 3 - 7
This should simplified using BODMAS rule.
B - Bracket
O - of
D - Division
M - Multiplication
A - Addition
S - Subtraction
=> First we should remove the bracket 3 + 6 × (5+4) ÷ 3 - 7
3 + 6 × 9 ÷ 3 - 7
=> Second division rule
3 + 6 × 3 - 7
=> Third Multiplication rule
3 + 18 - 7
=> Fourth Addison rule
21 - 7
=> And lastly subtraction rule
14
Hope my answer helps you :)
Regards,
Shobana
ABHAYSTAR:
Thank you !
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