Question

simply (3+underroot 3)(3-underroot 3)
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Answer 1

Answer:

(3+√3)(3-√3)

= 3²-(√3)² [ (a+b)(a-b)=a²-b²]

= 9-3

= 6

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Answer 2

Answer:

$(3 + \sqrt{3} )(3 - \sqrt{3} ) \\ 3(3 - \sqrt{3} ) + \sqrt{3} (3 - \sqrt{3} ) \\ 9 - 3 \sqrt{3} + 3 \sqrt{3} - 3 \\ 9 - 3 \\ 6$

Step-by-step explanation:

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