simply (3x²+2xy-2y²) (x+y)-(x²-xy+y²) (x-y)
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Answered by
0
Answer:
Step-by-step explanation:
(x + y)(2x + y) + (x + 2y)(x - y)
=> (2x² + xy + 2xy +y²) + (x² - xy + 2xy -2y²)
=> 2x² + x² + xy + 2xy - xy + 2xy + y² - 2y²
=>3x² + 4xy - y²
Answered by
0
Answer:
"2x³-y³+5x²y"
Step-by-step explanation:
= (3x²+2xy-2y²)(x+y)-(x²-xy+y²)(x-y)
= (3x³-2y³+5x²y)-(x³+y³)
= 3x³-2y³-x³-y³+5x²y
= 3x³-x³-2y³-y³
= 2x³-y³+5x²y Ans
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