Math, asked by stg53339, 3 months ago

simply:49×z-³/7-³×10×z-5(z#0)​

Answers

Answered by MysteriousMoonchild
27

Answer:

 =  \frac{49 \times  {z}^{ - 3} }{ {7}^{ - 3}  \times 10 \times  {z}^{5} }  \\  = multiply \: numerator \: and \: denominator \: with \:  {z}^{5}  \\  =  \frac{49 \times  {z}^{ - 3 + 5} }{ {7}^{ - 3} \times 10 \times  {z}^{ - 5 + 5}  }  =  \frac{49 \times  {z}^{2} }{ \frac{1}{7 {}^{3} }  \times 10}  \\  =  \frac{343 \times 49 \times  {z}^{2} }{10} or \:  \frac{ {7}^{3} \times  {7}^{2}  \times  {z}^{2}  }{10}  \\  =  \frac{16807 \times  {z}^{2} }{10} or \:   \frac{ {7}^{5} \times  {z}^{2}  }{10}  \\  = 1680.7 \times  {z}^{2}  \: or \:  \frac{ {7}^{5} \times  {z}^{2}  }{10}  \\  \\ hope \: its \: helpful \: to \: you \:

Answered by Anonymous
2

Here's your answer..

Hope it helps you..

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