Question

simply (5/9)²×(3/5)³×(3/5)⁰
please answer​

Answer 1

Step-by-step explanation:

Given:

$(5/9)²×(3/5)³×(3/5)⁰$

Answer:

$= (5/9)²×(3/5)³×(3/5)⁰$

use the formula or property of indices :

${a}^{m} \times {a}^{n}$

$= (5/9)²×(3/5 {)}^{0 + 3}$

now let's add 0 and 3 and find out the cube and square of the numbers

$= \frac{25}{81} \times \frac{27}{125}$

as you can see both the rational numbers are divisible by 3 and 5

$= \frac{ \cancel{25}}{ \cancel{81}} \times \frac{ \cancel{27 }}{ \cancel {125}}$

$= \frac{5}{27} \times \frac{9}{25}$

this can be further divided by 9 and 5

$= \frac{ \cancel {5}}{ \cancel {27}} \times \frac{ \cancel{9}}{ \cancel{25}}$

$= \frac{1}{3} \times \frac{1}{5}$

$= \frac{1}{15}$