Question

simply (9x-2y+z) power 2​

Answer 1

Step-by-step explanation:

(9x-2y+z)^2

(a-b+c)^2 = a^2 + b^2 + c^2 - ab - bc+ca [ identity used]

(9x-2y+z)

= 9x^2 + 2y^2 + z^2 - 9x × 2y - 2y × z + z × 9x

= 81x^2 + 4y^2 + z^2 - 18xy - 2yz + 9zx

in verbal form -:

81x square + 4y square + z square - 18xy - 2yz + 9zx..

that's ur answer....hope it helps you...

Answer 2

Step-by-step explanation:

we know that,

$(a + b + c)^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab - 2bc - 2ca$

Now,

$(9x - 2y + z)^{2} \\ = (9x)^{2} +( { - 2y}^{2}) + {z}^{2} - 2 \times 9x \times ( - 2y) - 2 \times ( - 2y) \times z - 2 \times z \times 9x \\ = 81 {x}^{2} - 4 {y}^{2} + {z}^{2} + 36xy + 4yz - 18zx$