Question

simply a(a²+a+1)+5 and find its value for (1) a=0, (2) a=1, (3) a= -1
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Answer 1

Simplify:

⟹ a ( a² + a + 1 ) + 5

⟹ a³ + a² + a + 5

( a³ + a² + a + 5 ) is the simplified form

If a = 0

⟹ a³ + a² + a + 5

⟹ (0)³ + (0)² + 0 + 5

⟹ 0 + 0 + 0 + 5

⟹ 5

If a = 0, the value of the polynomial will be 5

If a = 1

⟹ a³ + a² + a + 5

⟹ ( 1 )³ + ( 1 )² + 1 + 5

⟹ 1 + 1 + 1 + 5

⟹ 8

If a = 1, the value of the polynomial will be 8

If a = (-1)

⟹ a³ + a² + a + 5

⟹ (-1 )³ + (-1 )² + (-1 ) + 5

⟹ -1 + 1 - 1 + 5

⟹ - 1 + 5

⟹ 4

If a = 1, the value of the polynomial will be 8

Answer 2

Answer:

1) 5

2) 8

3) 4

Step-by-step explanation:

$a( {a}^{2} +a + 1) + 5$

${a}^{3} + {a}^{2} +a + 5$

1) a = 0

$0 + 0 + 0+ 5 = 5$

2) a = 1

$1 + 1 + 1 + 5 = 8$

3) a = -1

${( - 1)}^{3} + { (-1) }^{2} + ( - 1) + 5$

$- 1 + 1 - 1 + 5 = 4$