Question

simply (a+b)(2a-3b+2c) - 2c(2a-3b)​

Answer 1

Answer:

$(a+b)(2a-3b+2c) - 2c(2a-3b)= 2a^2 - 3b^2- ab - 2ac + 8bc$

Step-by-step explanation:

Simplify (a+b)(2a-3b+2c) - 2c(2a-3b)​

Find  (a+b)(2a-3b+2c)

= a (2a-3b+2c) + b (2a-3b+2c)

$= 2a^2 - 3ab + 2ac + 2ab- 3b^2 + 2bc$

Rearrange the similar terms

$= 2a^2 - 3b^2- 3ab+ 2ab + 2ac + 2bc$

$= 2a^2 - 3b^2- ab + 2ac + 2bc$

Now find 2c(2a-3b)​

= 2c(2a ) - 2c (3b)

= 4ac - 6bc

then (a+b)(2a-3b+2c) - 2c(2a-3b)​

 $= (2a^2 - 3b^2- ab + 2ac + 2bc) - ( 4ac - 6bc)\\ = 2a^2 - 3b^2- ab + 2ac + 2bc - 4ac + 6bc \\ = 2a^2 - 3b^2- ab + 2ac - 4ac+ 2bc + 6bc \\ = 2a^2 - 3b^2- ab - 2ac + 8bc$