SIMPLY a(b-c) + b(c-a) + c(a-b)
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Answered by
4
ab-ac+bc-ab+ac-bc
ab-ab+bc-bc+ac-ac
which is 0
ab-ab+bc-bc+ac-ac
which is 0
sonali978:
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Answered by
2
The answer is:-
ab-ac+bc-ab+ac-bc
=0
ab-ac+bc-ab+ac-bc
=0
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