Question

simply b.2√3/3 - √3/6
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Answer 1

Step-by-step explanation:

2

3

−

6

3

6

4

3

−

3

2

3

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Answer 2

Solution!!

$\sf \dfrac{2\sqrt{3}}{3}-\dfrac{\sqrt{3}}{6}$

Expand the fraction to get the least common denominator.

$\sf =\dfrac{2\sqrt{3}\times 2}{3\times 2}-\dfrac{\sqrt{3}}{6}$

Multiply the numbers in the numerator.

$\sf =\dfrac{4\sqrt{3}}{3\times 2}-\dfrac{\sqrt{3}}{6}$

Multiply the numbers in the denominator.

$\sf =\dfrac{4\sqrt{3}}{6}-\dfrac{\sqrt{3}}{6}$

Now that we have the same denominator, we can write all the numerators above a common denominator.

$\sf =\dfrac{4\sqrt{3}-\sqrt{3}}{6}$

If a negative term doesn't have a coefficient, it is considered that the coefficient is -1.

$\sf =\dfrac{4\sqrt{3}-1\sqrt{3}}{6}$

Collect the like terms by subtracting their coefficient.

$\sf =\dfrac{(4-1)\sqrt{3}}{6}$

Subtract the numbers.

$\sf =\dfrac{3\sqrt{3}}{6}$

Reduce the fraction with 3.

$\sf =\dfrac{\sqrt{3}}{2}$