simply (c) (2√5+3√2)² (d) (√5-√3)²
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(c) (2√5+3√2)²
= (2√5)^2 +(3√2)^2 + 2 (2√5)(3√2)
= 4 (5) + 9(2) + 12 √10
= 20 + 18 + 12 √10
= 38 + 12 √10
(d) (√5-√3)²
= (√5)^2 +(√3)^2 - 2(√5)(√3)
= 5 + 3 - 2√15
= 8 - 2√15
= (2√5)^2 +(3√2)^2 + 2 (2√5)(3√2)
= 4 (5) + 9(2) + 12 √10
= 20 + 18 + 12 √10
= 38 + 12 √10
(d) (√5-√3)²
= (√5)^2 +(√3)^2 - 2(√5)(√3)
= 5 + 3 - 2√15
= 8 - 2√15
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hope this will help you
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