simply it correctly
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1
(3x^2)^0
= 1
because (a)^0 = 1
(xy)^-2
= 1/(xy)^2
= 1/(x^2.y^2)
(-27a^9)^2/3
= (-3^3.a^9)^2/3
= (-3^2 . a^6)
= 9.a^6
Answered by
5
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I live you very much except my love
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