Math, asked by nishchalsrivastava, 1 year ago

simply log9-log3/log27

Answers

Answered by Anonymous
45

Question:

The question meant :-

( log 9 - log 3 ) / log 27

Answer:

\boxed{\red{\bf{\frac{1}{3}}}}

Step-by-step explanation:

( log 9 - log 3 ) / log 27

We know by the properties of logarithm that :

log a - log b can be written as log a / b

So we can write the above equation as :-

⇒ ( log ( 9/3 ) ) / log 27

⇒ log 3 / log 27

We know that 27 can be written as 3³ because 3 × 3 × 3 = 27 .

Hence :-

⇒ log 3 / log 3³

We know log aⁿ can be written as n log a .

Hence we get :-

⇒ log 3 / 3 log 3

⇒ 1/3

The value will be 1/3 .

Answered by patelvishva2007
2

Answer:

Question:

The question meant :-

( log 9 - log 3 ) / log 27

Answer:

Step-by-step explanation:

( log 9 - log 3 ) / log 27

We know by the properties of logarithm that :

log a - log b can be written as log a / b

So we can write the above equation as :-

⇒ ( log ( 9/3 ) ) / log 27

⇒ log 3 / log 27

We know that 27 can be written as 3³ because 3 × 3 × 3 = 27 .

Hence :-

⇒ log 3 / log 3³

We know log aⁿ can be written as n log a .

Hence we get :-

⇒ log 3 / 3 log 3

⇒ 1/3

The value will be 1/3 .

hope this is helpful

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