Math, asked by muruganarasi16, 7 months ago

simply: n+(m+1)+(n+2)+(m+3)+(n+4+)+(m+5)​

Answers

Answered by kirandeepkaur88476
1

Answer:

n+m+1+n+2+m+3+n+4+m+5=3n +3m+15=0

3(n+m+5)=0

n+m+5=0

n+m=-5

put n=0som=-5

put m=0n=-5

so the answer is -5please marks me brainlist dear

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