Math, asked by alifiyakhozema5, 8 months ago

Simply the following questions.​

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Answered by biligiri
0

Answer:

(v11) 4 √(3/5) + 1/2 √(27/5) + √(3/20)

4 √(3/5) + 1/2 √(9*3)/5 + √(3/4*5)

=> 4√(3/5) + 1/2*3√(3/5) + 1/2√(3/5)

=> 4√(3/5) + 3/2 √(3/5) + 1/2√(3/5)

=> 6 √(3/5)

[ √9 = 3 and √1/4 = 1/2 which are taken out from tne last two terms ]

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