Question

Simply the number given.

Answer 1

This is correct answer


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Answer 2

$= \frac{1}{ \sqrt{40}+ \sqrt{20}+ \sqrt{10}- \sqrt{50} }$

$= \frac{1}{ \sqrt{4*10}+ \sqrt{4*5}+ \sqrt{10}- \sqrt{25*2} }$

$= \frac{1}{ 2\sqrt{10}+ 2\sqrt{5}+ \sqrt{10}- 5\sqrt{2} }$

$= \frac{1}{ 3\sqrt{10}+ 2\sqrt{5}- 5\sqrt{2} }$

$= \frac{1}{ (3\sqrt{10}+ 2\sqrt{5}) - 5\sqrt{2} } * \frac{(3\sqrt{10}+ 2\sqrt{5}) + 5\sqrt{2}}{(3\sqrt{10}+ 2\sqrt{5}) + 5\sqrt{2}}$

$= \frac{(3\sqrt{10}+ 2\sqrt{5}) + 5\sqrt{2}}{(90+ 20+12 \sqrt{50} ) - 50}$

$= \frac{(3\sqrt{10}+ 2\sqrt{5}) + 5\sqrt{2}}{(60+12 \sqrt{50} }$

This is the most simplified form without substituting the values.
If you want to sunstitute the values of √2,√3 and√5 the it will become
=$\frac{(3\sqrt{10}+ 2\sqrt{5}) + 5\sqrt{2}}{(60+12 \sqrt{50} } = 0.1451$