Math, asked by harishhl7cr7, 8 days ago

Simply the question.

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Answered by Atlas99
6

(81)^{ \frac{3}{4} } -  \bigg( \frac{1}{32} \bigg)^{ - \frac{2}{5}} + (8)^{ \frac{1}{3}} \:  \bigg( \frac{1}{2} \bigg)^{ \frac{1}{2}} - (2)^{0} \\

 = 8^{ \frac{3}{4}} -  \bigg(\frac{1}{32} \bigg)^{ -  \frac{2}{5} } + {8}^{ \frac{1}{3} } \bigg( \frac{1}{2} \bigg)^{ \frac{1}{2} } - 1 \\

 = 27 - 4 + 2 \frac{1}{2} - 1 \\

 = 22 +  {2}^{ \frac{1}{2} } \\

 = 23.

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