simply this question with the help of bodmas
9÷3(2+1)=?
Answers
Answer:
9/3(2+1)
/3(2+1) = 93(2+1)
/3(2+1) = 93(2+1) Grouping symbols
/3(2+1) = 93(2+1) Grouping symbols= 93(3)
/3(2+1) = 93(2+1) Grouping symbols= 93(3) Simplify division because it's on the left.
/3(2+1) = 93(2+1) Grouping symbols= 93(3) Simplify division because it's on the left.= (3) (3)
/3(2+1) = 93(2+1) Grouping symbols= 93(3) Simplify division because it's on the left.= (3) (3) = 9
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → Bracket
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →Of
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →Division
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → Multiplication
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition and
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → Subtraction
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division9/3 = 3
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division9/3 = 3The question becomes → 3*3
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division9/3 = 3The question becomes → 3*3Finally, we solve multiplication
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division9/3 = 3The question becomes → 3*3Finally, we solve multiplication3*3 = 9
It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division9/3 = 3The question becomes → 3*3Finally, we solve multiplication3*3 = 9Hence 9 (nine) is the final answer.