Math, asked by shivamkt2203, 6 months ago

simply this question with the help of bodmas
9÷3(2+1)=?​

Answers

Answered by Anonymous
0

Answer:

9/3(2+1)

/3(2+1) = 93(2+1)

/3(2+1) = 93(2+1) Grouping symbols

/3(2+1) = 93(2+1) Grouping symbols= 93(3)

/3(2+1) = 93(2+1) Grouping symbols= 93(3) Simplify division because it's on the left.

/3(2+1) = 93(2+1) Grouping symbols= 93(3) Simplify division because it's on the left.= (3) (3)

/3(2+1) = 93(2+1) Grouping symbols= 93(3) Simplify division because it's on the left.= (3) (3) = 9

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → Bracket

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →Of

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →Division

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → Multiplication

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition and

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → Subtraction

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division9/3 = 3

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division9/3 = 3The question becomes → 3*3

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division9/3 = 3The question becomes → 3*3Finally, we solve multiplication

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division9/3 = 3The question becomes → 3*3Finally, we solve multiplication3*3 = 9

It is a simple mathematical problem, with application of B.O.D.M.A.S. i.e.B → BracketO →OfD →DivisionM → MultiplicationA →Addition andS → SubtractionThis is the precedence order for the arithmetic operators.Here the question is :9/3(2+1)First we solve the bracket.2+1 = 3The question becomes → 9/3*3Now we solve division9/3 = 3The question becomes → 3*3Finally, we solve multiplication3*3 = 9Hence 9 (nine) is the final answer.

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