Simply (x-2y)(y+3x)+(X+y)(2x-y)+(X+3y)(x-y)
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Step-by-step explanation:
Given,
(x-2y)(y+3x)+ (x+y)(2x-y)+(x+3y)(x-y)
= x y - 3 x square - 2 y square - 6 X Y + 2 x square minus x y + 2 x y - X square + x square -xy +3xy-3y square
= by cancellation,
we get,
=-3xy
hence,-3xy
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