Question

simplyfy (3x-5y+7z)2+(3x+5y-7z)2​

Answer 1

Answer:

11x−[8y−{11x−(7z−3y)+5y−(3x−2y−z)}]

11x−[8y−{11x−7z+3y+5y−3x+2y+z}]

11x−[8y−11x+7z−3y−5y+3x−2y−z]

11x−[−8x−2y+6z]

11x+8x+2y−6z

19x+2y−6z

Answer 2

Step-by-step explanation:

$(3x - 5y + 7z)2 + (3x + 5y - 7z)2$

Distribute 2 through the parentheses

$6x - 10y + 14z + (3x + 5y - 7z) \times 2$

Since two opposites add up to zero, remove them from the expression

$6x + 14z + 6x - 14z$

$6x + 6x$

$12x$

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