Math, asked by chakridarnasi, 1 year ago

simplyfy 789^3+211^3/(789^2-789*211+211^2)

Answers

Answered by amitsinghto36
1
let 789 be a
and 211 be b
so, a³ + b³ /a² - ab + b²
now, (a+b)(a² - ab + b²)/ a² - ab + b² = a + b = 789 + 211 = 1000
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