Question

simplyfy and solve the following linear equation b2-(b-1)(b+2)/3=1/5​

Answer 1

Answer:

b2-(b-1) ( b+2)/3=1/5

b2- (b-1)(b+2)= 3/5

b2 -b +1 (b+2)=3/5

b2-b^2- b2 + b +2=3/5 (( b^2 = b square ))

-b^2 + b +2=3/5

-b^2 + b = 3/5-2

- b^2 + b = -7/5

- b^2+ b +7/5=0

-5b^2 + 5b + 7 =0

take - common

5b^2- 5b -7= 0

here is ur ans