Question

Simplyfy the denominator root 32 + root 48 by root 8 + root 12

Answer 1

Answer:

(√32 + √48)/(√8 + √12)

= (4√2 + 4√3)/(2√2+2√3)

= 4(√2+√3)/2(√2+√3)

= 4/2

=2

Answer 2

CORRECT QUESTION:

$\small{ \rm{Simplify \: : }} \\ \small{ \tt{ \frac{ \sqrt{32} + \sqrt{48} }{ \sqrt{8} + \sqrt{12} } }}$

ANSWER:

√32 = 4√2

√48 = 4√3

√8 = 2√2

√12 = 2√3

Simplying we get

${ \tt{ : \to \dfrac{4 \sqrt{2} + 4\sqrt{3} }{2 \sqrt{2} + 2 \sqrt{3} } }}$

Taking common

$: \to{ \tt{ \frac{ \cancel{4} \cancel{( \sqrt{2} + \sqrt{3} ) }}{ \cancel2 \cancel{( \sqrt{2} + \sqrt{3} )}} = 2 }}$

Hence

$\therefore{ \bf{ \dfrac{ \sqrt{32} + \sqrt{48} }{ \sqrt{8} + \sqrt{12} } \to 2 }}$

CONCEPT USED:

♦ Surds