Math, asked by LegendaryHS, 7 months ago

Simplyfy (√x)⅔√y⁴÷√xy-½ is​

Answers

Answered by santhoshkalam19
1

your answer is here buddy.....

Given:

\dfrac{(\sqrt{x})^{\frac{-2}{3}}\sqrt{y^4}}{\sqrt{xy^{\frac{-1}{2}}}}

xy

2

−1

(

x

)

3

−2

y

4

\textbf{To find:}To find:

\text{Simplified form of the given expression}Simplified form of the given expression

\textbf{Solution:}Solution:

\text{Consider,}Consider,

\dfrac{(\sqrt{x})^{\frac{-2}{3}}\sqrt{y^4}}{\sqrt{xy^{\frac{-1}{2}}}}

xy

2

−1

(

x

)

3

−2

y

4

=\dfrac{(x^{\frac{1}{2}})^{\frac{-2}{3}}\,y^2}{(xy^{\frac{-1}{2}})^{\frac{1}{2}}}=

(xy

2

−1

)

2

1

(x

2

1

)

3

−2

y

2

=\dfrac{x^{{\frac{1}{2}}{\times}{\frac{(-2)}{3}}}\,y^2}{x^{\frac{1}{2}}y^{{\frac{-1}{2}}{\times}{\frac{1}{2}}}}=

x

2

1

y

2

−1

×

2

1

x

2

1

×

3

(−2)

y

2

=\dfrac{x^{\frac{-1}{3}}\,y^2}{x^{\frac{1}{2}}y^{\frac{-1}{4}}}=

x

2

1

y

4

−1

x

3

−1

y

2

=x^{\frac{-1}{3}-\frac{1}{2}}\,y^{2+\frac{1}{4}}=x

3

−1

2

1

y

2+

4

1

=x^{\frac{-2-3}{6}}\,y^{\frac{8+1}{4}}=x

6

−2−3

y

4

8+1

=x^{\frac{-5}{6}}\,y^{\frac{9}{4}}=x

6

−5

y

4

9

\textbf{Answer:}Answer:

\textbf{The simplified form of the given expression is $\bf\,x^{\frac{-5}{6}}\,y^{\frac{9}{4}}$}The simplified form of the given question

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