simplyfy ( x2 - 3x + 2 ) ( x + 2 )
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2
[x^2-2x-x+2](x+2)
[x(x-2)-1(x-2)](x+2)
(x-2) (x-1) (x+2) answer
[x(x-2)-1(x-2)](x+2)
(x-2) (x-1) (x+2) answer
Ayush7860:
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how you will do this sum
by polynomial rule
first factor rule
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Answered by
1
(x2 - 3x + 2) (x + 2)
= x(2x - 3x + 2) + 2(2x - 3x + 2)
= 2x^2 - 3x^2 + 2x + 4x - 6x + 4
= -x^2 + 4
= x(2x - 3x + 2) + 2(2x - 3x + 2)
= 2x^2 - 3x^2 + 2x + 4x - 6x + 4
= -x^2 + 4
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