Question

Simplyify using indentity : (99) who's power 2​

Answer 1

$\red{ 99^{2}}$

$= ( 100 - 1 )^{2}$

/* By Algebraic Identity */

$\boxed { \pink { ( a- b)^{2} = a^{2} - 2ab + b^{2} }}$

$= 100^{2} - 2 \times 100 \times 1 + 1^{2}$

$= 10000 - 200 + 1$

$= 9800 + 1$

$= 9801$

Therefore.,

$\red{ 99^{2}} \green { = 9801}$

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