Question

Simran borrowed Rupees 180000 at 8% for 2.5 years find the simple interest and amount she has to pay​

Answer 1

Answer:

Given

Money borrowed (P) = Rs 18000

Rate (R) = 8% p.a.

Time (n) = 2 years

Simple Interest = PRT / 100

= Rs (18000 × 8 × 2) / 100

= Rs 2880

In case of compound interest

A = P {1 + (R / 100)}

n

= Rs 18000 {1 + (8 / 100)}

2

= Rs 18000 × (27 / 25)

2

= Rs 18000 × (27 / 25) × (27 / 25)

We get,

= Rs 104976 / 5

= Rs 20995.20

Hence,

Compound interest = Amount – Principal

= Rs 20995.20 – Rs 18000

= Rs 2995.20

Now,

Difference between compound interest and simple interest

= Rs 2995.20 – Rs 2880

= Rs 115.20

Step-by-step explanation:

mark as brainlist please

Answer 2

Step-by-step explanation:

Mark me as BRAINLIST..