Simran travelled (3m square 2+3n+4) km straight on a road and then came back to ( 3n + m square 2 + 2) km on the same road. How far is she now from the starting point?
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Answer:
Step-by-step explanation:
B is the finishing point and is 10 km from the point A The aerial distance of A from B is 10 km calculated as below (AB)
2
=(AD)
2
+(DB)
2
=(8)
2
+(6)
2
=64+36=100
∴ AB = 10 km
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