Question

Simultaneous equation is 5x+2y=-3,x+5y=4

Answer 1

Answer:

5x + 2y + 3 =0. - 1

x+5y-4 =0. -2

By substitution method

from 2 put the value of x in 1

x = 4-5y

5(4-5y) + 2y + 3 = 0

20 -25y +2y + 3 =0

23 -23y = 0

23 = 23y

1 =y

put the value of y in equation 1

5x + 2 +3 =0

5x+5=0

5x = -5

x = -1

y =1

Answer 2

Answer:

5x + 2y = –3 .....(I)

x + 5y = 4 .....(II)

Multiply (II) with 5 we get

5x + 25y = 20 .....(III)

Subtracting (III) from (I) we get

5x−5x+2y−25y=−3−20

⇒−23y=−23

⇒y=−23−23=1

Putting the value of y = 1 in (II) we get

x+5(1)=4⇒x+5=4⇒x=4−5=−1

Thus, (x, y) = (−1, 1)