simultaneous equation solve for 3(2u+v)=7uv and 3(u+3v)=11uv find the value of "u" and "v"
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6u + 3v=7uv
3u + 9v=11uv
multiply 1st equation by 3 and 2nd by 6
we get
18u + 9v=21uv
18u + 54v=66uv
subtract the two equations
45v=45
v=1
substitute in any equation and you can get the value of u
6u+3×1=7×u×1
u=3
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3u + 9v=11uv
multiply 1st equation by 3 and 2nd by 6
we get
18u + 9v=21uv
18u + 54v=66uv
subtract the two equations
45v=45
v=1
substitute in any equation and you can get the value of u
6u+3×1=7×u×1
u=3
Mark it as branliest plz if u like the answer
EINSTEINGENIOUS:
wrong answer
sorry
the value of" u "is 1 and" v" is 3/2
u may check my calculations
it's exactly correct dear
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