Question

Simultaneous equations 6a+3b=4 A+b=1

Answer 1

Step-by-step explanation:

6a+3b=4

a+b=1

b=1-a

substitute into first equation

6a+3(1-a)=4

6a+3-3a=4

3a=1

a=(1/3)

b=(2/3)

6*(1/3)=2

3*(2/3)=2

and 6a+3b=4