Simultaneous equations. solve
2x + 3y = 4 x + y = 6
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Hello mate....❤
here is your answer..✌
Equ.1 - 2x+3y=-4
Equ.2 - x-y=6
x-y=6
x=6+y (sub. this 'x' in equ.1)
2(6+y)+3y=-4 (multiple 2 with (6+y))
12+2y+3y=-4 (add 2y+3y)
12+5y=-4 (subtract 12 on both sides)
12–12+5y=-4–12 (then it comes to)
5y=-16 (divide both sides with 5)
5y/5=-16/5
Y=-16/5 (we got 'y' value then put it on equ.1or.2)
x-(-16/5)=6 (- × - = +) we get
x+(16/5)=6 (subtract (16/5) on both sides)
x+(16/5)-(16/5)=6-(16/5)
X=((6×5)-16)/5
x=(30–16)/5
x=14/5.
The value of x=(14/5) & y=(-16/5).
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