Simultaneous equations :-
three times the larger of the two numbers is divided by the smaller , then the quotient is 4 and remainder is 5 . If 6 times the smaller is divided by the larger , the quotient is 4 and tge remainder is 2 . Find the numbers .
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Step-by-step explanation:
Let the two numbers be x and y ,where x be larger than y.
According to question:
[By substituting the values in: divident=divisor(quotient)+remainder]
3x=4y+5
(3x-4y=5)4
12x-16y=20---(1).
(6y=4x+2)3
18y=12x+6
-12x+18y=6----(2)
(1)+(2). [ Elimination method]
12x-16y=20
-12x+18y=6
2y=26
y=26/2=13.---(3)
(-12x+18y=6)/2
{-6x+9y=3)/3
-2x+3y=1---(4)
substitute. (3) In (4):
-2x+3(13)=1
-2x+39=1
39-1=2x
38/2=x
19=x.
Hence the two numbers are 19 and 13.
Hope helps you.
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