Question

•●○ sin 0 (1 + tan 6) + cos 0 (1 + cot O) = (sec 0 + cosec )
[CBSE 2008]​

Answer 1

Answer:

Step-by-step explanation:

According to given sum,

sin (1+tan)+cos (1+cot)=sec+cosec

=> LHS= sin (1+tan)+cos (1+1/tan)

=> sin (1+tan)+cos (1+tan)/tan

=> (1+tan)(sin+cos/tan)

=> (1+tan)(sin.tan+cos)/tan

=> (1+tan)(sin^2/cos+cos)/tan

=> (1+tan)(sin^2+cos^2)/tan.cos

=>(1+tan)/tan.cos

=>(1/tan.cos)+tan/tan.cos

=>( cot/cos)+(1/cos)

=> cosec +sec

LHS= RHS.

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