sin 0 = 15/17 what is value of tan 0
Answers
Answered by
1
Ans : SinO = P/H
By Pythagorean theorem,
(H)^2 = (P)^2 + (B)^2
(17)^2=(15)^2 + (B)^2
289 = 225 + (B)^2
289 - 225 = (B)^2
64 = (B)^2
B = 8
Tan O = P/B
= 15/8
Hope it helps...!!
By Pythagorean theorem,
(H)^2 = (P)^2 + (B)^2
(17)^2=(15)^2 + (B)^2
289 = 225 + (B)^2
289 - 225 = (B)^2
64 = (B)^2
B = 8
Tan O = P/B
= 15/8
Hope it helps...!!
Similar questions