Question

sin 0 - 2 sin e
2 cos' 0 -- cos e
o = tan o​

Answer 1

Step-by-step explanation:

First of all we remember all the degree of value of sin,cos,tan,cot,sec and cosec

Now come to the question....

The value of sin0= 0

and the value of cos0=1

now put the value of sin 0 and cos 0 ....given in the question

(sin 0+cos 0)^2 +( sin 0-cos 0)^2

here we use the (a+b)^2=a^2+b^3+2a.b

rule and (a-b)^2=a^2+b^2-2.a.b

(0^2+1^2+2.0.1)+ (0^2+1^2-2.0.1)

=0+1+0+0+1-0

=2( proved)

hope it will help you ☺️

Answer 2

$\huge\star\mathfrak\blue{{Answer:-}}$

First of all we remember all the degree of value of sin,cos,tan,cot,sec and cosec

Now come to the question....

The value of sin0= 0

and the value of cos0=1

now put the value of sin 0 and cos 0 ....given in the question

(sin 0+cos 0)^2 +( sin 0-cos 0)^2

here we use the (a+b)^2=a^2+b^3+2a.b

rule and (a-b)^2=a^2+b^2-2.a.b

(0^2+1^2+2.0.1)+ (0^2+1^2-2.0.1)

=0+1+0+0+1-0

=2( proved)